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Unregulated dual 26650 box mod question

jlaw30

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Don't know if this is the right place to post so here's my go at it.

Found a guy who makes what is essentially a mech box mod. Unregulated, dual 26650 in parallel.

So volts remain same, amperage doubles. Basically, how do I figure out the wattage with this? Do I just double the amperage of the batteries? Use the MNKE 26650s as a benchmark, do I use the continuous discharge current of 20A or the pulse discharge of 60A?

It's late, I'm tired so I'm getting confused quickly. Someone make me feel less dumb.
 

Spiralnebel

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http://www.the12volt.com/ohm/ohmslawcalculators.asp

the wattage depends on your resistance. (P = E 2 / R)
For example: If you have a 0.2 ohm coil and you use a fully charged battery with 4.2v the output watte is 88.2w
The pulse discharge means that you can hold the fire button pressed for max. 10 sec.at an amp limit of max. 60A,
if you fire constantly the mnke can be fired with max. 20a so not less resistance then 0.21 / pulse 0.07.

But dont forget to search as well for safty advices for using batteries in parallel !!
 

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