Hello community, so I'm sitting here bored and lately I've been wanting to try and twist my clapton wire, basically for fun. So how would I calculate the resistance this coil will come in at? Now I'm going to start with a single coil but to figure out the resistance can I treat as if a dual coil build. For ex. I'm using 26/32g kanthal. I generally go with 3mm id. With those numbers 8 wraps will give me 1.0 ohm. So if I twist 2 strands then wrap it 8x will the resistance be .5 ohms? Any feedback will be appreciated.
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? on anticipated resistance
- Thread starter rommel19540
- Start date
Steamengine.org. wire tab.
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Sent from my SCH-I605 using Tapatalk
Basicly yes it devides in half so if u would dual it up ends up around 0.25
Hey thank you, much appreciated
you're welcome
Honestly I don't know but wouldn't it matter on how much it's twisted? Loose vs tightly twisted?
Yea should change the resistance slightly wouldn't be too much
I like a looser twist and spaced coils with twisted builds.
I like to twist my wire to a pitch of 0(para)to about 1mm. IMO, any tighter you might as well just use fatter wire. The tighter the twist the higher the resistance of the wire. Have you tried modeling some twisted build on Steam-Engine.org.....
7 wraps of 26awg Kanth in parallel or as single strand dual coil on 3mm is about .5ohm, Twist those same wires to 1mm pitch 7 wraps is .7ohm coil with about 3x the surface area.