Vaping Maths

[Cloudy Coils]

Hi,

I thought it would be great to share some of the physics I have been working on with this community. If I made a mistake, you can point it out and I shall edit the post to be correct. If not, please use these formulas to find the temperature change, necessary weight of your wires, length of your wires, and watts.

Here is the Specific Heat formula solved for Temperature Change (per second):
(Temperature Change in °C or °K) =
Watts / (Mass in grams * Heat Capacity in Joules per gram)

Here is the law solved for grams:
(Mass in grams) = Watts / (Heat Capacity * Temperature Change)

And for Watts:
Watts = Mass in grams / (Heat Capacity * Temperature Change)

Here is how to calculate how many watts are in your vape:
Watts = (Current * Voltage) = (Current * Current * Total Resistance)

Here are some websites to make finding other numbers easier:
http://kanthal.com/en/products/mate...heating-wire-and-resistance-wire/kanthal-a-1/
http://www.wolframalpha.com/
http://www.ohmslawcalculator.com/ohms-law-calculator
http://www.temcoindustrialpower.com/products/Resistance_Wire/RW0359.html

Some tips to remember when using Ohm's Law is to only use two values to find the rest, or it does not work.
The temperature change formula above is temperature added every second.

 

[Cloudy Coils]

Here are the values of Heat Capacity for Kanthal A1 at various temperatures

 

[ZoeBoy]

Welcome to VU. Glad you're here. Thanks for sharing the info.

 

[SaintSkinny51792]

good deal! Ill have to add these to my "vape equation" poster, I got sick of having to look up formulas so I put the ones I use regularly on my wall lol a little trick to help with living with ADHD

 

[Cloudy Coils]

It is possible to also solve for grams in the heat equation to get exactly how much juice per second is being heated if you like that, counting in the thermal conductivity of the coil and cotton. I am investigating the resistance of a standard Clapton coil as opposed to a thicker wire with less resistance and surface area.
To find the resistance of multiple coils in parallel that are all the same, use something similar to integration:
Resistance^(number of wires-1) / (number of wires) = Final Resistance
in most cases just do:
Resistance/(number of wires) = Final Resistance
I'm right there with you about the ADD stuff, have a good day.