I don’t know what you want. Before you can apply numbers to something, you have to understand the concept. I’ll state it again. Build resistance has nothing to do with what’s going on with the input side of the chip. Only watt setting does. Don’t believe me? Check steam engine. The runtime tab shows you can change resistance to whatever you want and runtime stays the same if watt setting doesn’t change.
It's not I don't believe you boomstick I'm just not familiar with everything you are saying and I freely admit I need to learn more about the converters I have no problem admitting that.
I did go and check out the battery page as you say and agree it didn't affect run time changing the resistence. Perhaps the bit I'm getting hung up on is the notes below that calculator, they seem to follow parts I posted ....at least in my example posted in terms of input and output calculations but the run time does appear to be different so I need to understand how to work that part out and go through the theory ....
Source steam engine....
http://www.steam-engine.org/batt.html
"Regulated mods – fixed or variable voltage or power
Regulated mods are more difficult to model. But even though they are much more complex than mechs, with some selective simplification we can safely ignore most of the complexity. So we break these mods down into two circuits and a
black box. This makes our regulated mod model little more than twice as complex as our mech mod model.
The two main circuits of a regulated mod are:
- The atomizer (output) side.
- The battery (input) side.
And never the twain shall meet. The regulator circuit takes care of that. It can have a bunch of more or less advanced circuits in itself, and it uses a little bit of power, but for the most part we can envision it as a black box separating the battery circuit from the atty circuit.
Tread carefully – here be pitfalls
Since we are looking at two separate circuits, you can never mix numbers from both sides of the regulator in your calculations. For instance: You cannot determine the current drained from the battery by measuring the resistance of the coil and the voltage of the battery. Using the resistance from one circuit, and the voltage from a different circuit, will result in a nonsensical answer. Nor can you determine the current going through the coil by determining the current from the battery.
Output – the atomizer
On the atomizer side, the voltage is ideally whatever the user has selected, but keep in mind that some APVs promise more than they keep. If you set the voltage to 5V, are you confident that the APV actually delivers 5V? Unless you know that your APV is accurate, you might want to measure and confirm the output voltage under load.
Variable wattage devices work like variable voltage devices, for the most part. The difference is that they measure the atomizer resistance, and uses this measurement, and Ohm's law, to calculate what voltage to set in order to reach your desired power.
Likewise, knowing the output voltage and resistance, you can calculate the output current and power yourself.
Input – the battery
On the battery side, the voltage is whatever the battery has in it at the moment, just like with mech mods. The power, however, is
whatever the regulator needs to pull in order to deliver the desired voltage to the atomizer at any given time. So by dividing the power by the (ever decreasing) battery voltage, we find the (ever increasing) current.
Transfer the power – getting down to it
So how can our measured resistance tell us anything about battery drain? Well, there is one way to "transfer information" from one side of the regulator to the other. The trick is simple; to paraphrase some old movie: Use the power, Luke!
The power hitting the atomizer equals the power flowing from the battery, minus the power used by the regulator circuit.
These regulator circuits typically boast an efficiency between 80–95%. In practice this means that the regulator "steals" about a tenth of the power from the battery.
Knowing this, we can use our multimeter and Ohm's law to calculate what is going on at either side of the regulator. Then we can convert it to Watts, and voila! Subtracting (or adding) the loss in the regulator circuit, we now know the power on the other side as well.
Lastly, we use Ohm's law again, break down the power to current and voltage, and that's that: We now have all the numbers we need."